Matematika Sekolah Menengah Pertama tentukan hasil perpangkatan berikut! a.(2/7)-³ b.((1/5)²)-²​

tentukan hasil perpangkatan berikut! a.(2/7)-³ b.((1/5)²)-²​

( 2/7 )-³

= ( 7/2 )³

= ( 7/2 ) . ( 7/2 ) . ( 7/2 )

= ( 7.7.7 )/( 2.2.2 )

= 343/8

= 42 7/8

(( 1/5 )²)-²

= ( 1/5 )^2 × ( -2 )

= ( 1/5 )-⁴

= ( 5/1 )⁴

= 5⁴

= (5.5.5.5)

= 25 × 25

= 625

Penjelasan dengan langkah-langkah:

Rumus → [tex]{(\frac{a}{b})}^{-n} = {(\frac{b}{a})}^n[/tex]

Nomor A

[tex] = {( \frac{2}{7} )}^{ - 3} [/tex]

[tex] = {( \frac{7}{2} )}^{3} [/tex]

[tex] = \frac{ {7}^{3} }{ {2}^{3} } [/tex]

[tex] = \frac{7 \times 7 \times 7}{2 \times 2 \times 2} [/tex]

[tex] = \frac{343}{8} [/tex]

[tex] \: [/tex]

Nomor B

[tex] = { ({( \frac{1}{5} )}^{2} )}^{ - 2} [/tex]

[tex] = {( \frac{1}{5} )}^{2 \times ( - 2)} [/tex]

[tex] = {( \frac{1}{5} )}^{ - 4} [/tex]

[tex] = {( \frac{5}{1} )}^{4} [/tex]

[tex] = {5}^{4} [/tex]

[tex] = 625[/tex]

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